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-rwxr-xr-xcontests/Round901/B/main.cpp111
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diff --git a/contests/Round901/B/main.cpp b/contests/Round901/B/main.cpp
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+++ b/contests/Round901/B/main.cpp
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+#include <bits/stdc++.h>
+#include <climits>
+
+using namespace std;
+
+using ll = long long;
+using pii = pair<int, int>;
+using vpii = vector<pii>;
+using vi = vector<int>;
+using vll = vector<long long>;
+using mpii = map<int, int>;
+using mpll = map<ll, ll>;
+using db = long double;
+
+#define pb push_back
+#define all(x) (x).begin(), (x).end()
+#define rall(x) (x).rbegin(), (x).rend()
+#define lb lower_bound
+#define ub upper_bound
+#define make_unique(x) \
+ sort(all((x))); \
+ (x).resize(unique(all((x))) - (x).begin())
+#define ceil(a, b) ((a) + (b)-1) / (b)
+
+const int mod = (int)1e9 + 7;
+const db pi = acos((db)-1);
+const int dx[4]{1, 0, -1, 0};
+const int dy[4]{0, 1, 0, -1};
+
+#ifdef LOCAL
+#include "debug.h"
+#else
+#define dbg(...) 42
+#endif
+
+/* stuff you should look for:
+ ---------------------------
+ * special cases (n=1?)
+ * int overflow, array bounds
+ * do smth instead of nothing and stay organized
+ * WRITE STUFF DOWN
+ * DON'T GET STUCK ON ONE APPROACH
+ */
+
+void solve() {
+ int n, m, k;
+ cin >> n >> m >> k;
+ vll a(n), b(m);
+ ll min_a = INT_MAX;
+ ll min_b = INT_MAX;
+ ll max_a = 0;
+ ll max_b = 0;
+ ll sum = 0;
+ for (auto &x : a) {
+ cin >> x;
+ sum += x;
+ min_a = min(min_a, x);
+ max_a = max(max_a, x);
+ }
+ for (auto &x : b) {
+ cin >> x;
+ min_b = min(min_b, x);
+ max_b = max(max_b, x);
+ }
+ ll mx = max(max_a, max_b);
+ ll mn = min(min_a, min_b);
+ ll tmp = sum + (max_b - min_a);
+ if (mx == max_a && mn == min_a) {
+ if (k % 2 == 1) {
+ cout << tmp << '\n';
+ } else {
+ cout << tmp + (mn - mx) << '\n';
+ }
+ } else if (mx == max_b && mn == min_b) {
+ if (k % 2 == 1) {
+ cout << tmp << '\n';
+ } else {
+ cout << tmp + (mn - mx) << '\n';
+ }
+ } else if (mx == max_a && mn == min_b) {
+ if (k % 2 == 1) {
+ if (max_b <= min_a) {
+ cout << sum << '\n';
+ } else {
+ cout << tmp << '\n';
+ }
+ } else {
+ if (max_b <= min_a) {
+ cout << sum + (mn - mx) << '\n';
+ } else {
+ cout << tmp + (mn - mx) << '\n';
+ }
+ }
+ } else {
+ if (k % 2 == 1) {
+ cout << tmp << '\n';
+ } else {
+ cout << sum << '\n';
+ }
+ }
+}
+
+int main() {
+ ios_base::sync_with_stdio(false);
+ cin.tie(NULL);
+ int tt;
+ cin >> tt;
+ while (tt--) {
+ solve();
+ }
+}